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If the heat of combustion for a specific compound is -1370.0 kJ/mol and its molar mass...

If the heat of combustion for a specific compound is -1370.0 kJ/mol and its molar mass is 40.13 g/mol, how many grams of this compound must you burn to release 458.60 kJ of heat?

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Answer #1

Molar mass of the compound = 40.13 g/mol
​So, 1 mole of compound = 40.13 g

Now, heat of combustion of the compound = -1370.0 kJ/mol
The negative sign is due to the heat released.
So, 1370.0 kJ of heat is released by 1 mole of compound
or, 1370.0 kJ of heat is released by 40.13 g of compound
or, 1 kJ of heat is released by (40.13 / 1370) g of compound
or, 1 kJ of heat is released by 0.029 g of compound
or, 458.6 kJ of heat is released by (458.6 x 0.029) g of compound
or, 458.6 kJ of heat is released by 13.3 g of compound​.

So, 13.3 g of the compound must you burn to release 458.60 kJ of heat.

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