Question

The octane in gasoline burns according to the following equation: 2C8H18 + 25O2 16CO2 + 18H2O How many moles of O2 are needed to react fully with 4.99 mol of octane? How many moles of CO2 can form from 0.658 mol of octane? How many moles of water are produced by the combustion of 5.85 mol of octane? If this reaction is used to synthesize 5.42 mol of CO2, how many moles of oxygen are needed? How many moles of octane?

Answer 1

2C8H18 + 25O2 ----------------> 16CO2 + 18H2O

2 moles octane require 25 moles of O2

4.99 moles of octane require 4.99 x 25 / 2 = 62.37

moles of O2 require = 62.37

2 moles octane gives 16 moles of CO2

0.658 moles octane gives 0.658 x 16 /2 = 5.264

moles of CO2 produced = 5.264

2 moles of octane gives 18 moles H2O

5.85 moles of octane gives 5.85 x 18 / 2 = 52.65

moles of H2O formed = 52.65

16 moles CO2 require 25 moles O2

5.42 moles CO2 require 5.42 x 25 / 16 = 8.47

moles of O2 require = 8.47

16 moles of CO2 require 2 moles octane

5.42 moles CO2 require 5.42 x 2 / 16 = 0.68

moles of octane required = 0.68