Question

Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH...

Calculate ΔHrxn for the following reaction:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Use the following reactions and given ΔH′s.
2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH = -824.2 kJ
CO(g)+1/2O2(g)→CO2(g), ΔH = -282.7 kJ

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Answer #1

2Fe(s) + 3/2O2(g) ---> Fe2O3(s). DeltaH = -824.2kJ

Inversing the reaction we get-

Fe2O3(s) ---> 2Fe(s) + 3/2O2(g). DeltaH = +824.2kJ. ......(1)

CO(g) + 1/2O2(g) --->CO2(g). DelataH = -282.7kJ

Multiplying by 3-

3CO(g) + 3/2O2(g) ---> 3CO2(g). DeltaH = 3*-287.7 = -863.1kJ

Adding this reaction to reaction 1 we get-

Fe2O3(s)+3CO(g)+3/2O2(g)--->2Fe(s)+3/2O2(g)+3CO2

Cancelling same terms we get-

Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g)

Delta Hrxn = +824.2kJ -863.1kJ = -38.9kJ

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