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Using the unit conversion method derive an eqauation to calculate the heat produced from the HCl-NaOH...

Using the unit conversion method derive an eqauation to calculate the heat produced from the HCl-NaOH reaction, and write your equation in sample caculation A.

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Answer #1

Heat of neutralisation can be measured using a styrofoam cup solution calorimter:

The enthalpy change, ΔH, for the neutralisation reaction:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

(i) heat produced = mass of reaction mixture × specific heat capacity of solution × temperature change

(ii) enthalpy change for the reaction = -heat produced

(iii) molar heat of neutralisation = enthalpy change ÷ moles (of water produced)

Molar heat of neutralisation for reactions between dilute aqueous solutions of strong acid and strong base is always the same, that is,

  • ΔHneut = -55.90 kJ mol -1

    because no bonds need to be broken, and because making the H-O bonds in H2O releases energy

    (breaking bonds is an endothermic process, making bonds is an exothermic process).

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