Question

A- Write the neutralization reaction which occur between potassium hydroxide and acetic acid (im having problems understanding how to do this, could you explain?)

B- In lab, the concentration of bases like NaOH is frequently determined by standardization i.e., titration using a substance of known molar mass. The substance most commonly used is potassium hydrogen phthalate (KHP, KC8H5O4). What is the concentration of sodium hydroxide if 0.51 g of KHP neutralize 25.65 mL of sodium hydroxide?-

Answer 1

A) neutralization reaction :

KOH(aq) + CH3COOH(aq) ----> CH3COOK(aq) + H2O(l)

b)

KHP + NaOH ---> KNaP + H2O

1 mol KHP = 1 mol NaOH

no of mol of KHP reacted = w/Mwt

                         = 0.51/204.22

           = 0.0025 mol

no of molof NaOH reacted(n) = 0.0025 mol = 2.5 mmol

volume of NaOH reacted(v) = 25.65 ml

concentration of NaOH (M) = n/v

      = 2.5/25.65

      = 0.0975 M