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If sodium methoxide in methanol was used in place of potassium t-butoxide in t-butanol, your GC...

If sodium methoxide in methanol was used in place of potassium t-butoxide in t-butanol, your GC analysis would look much more like the 2-butanol/sulfuric acid reaction products. In addition, a new, non-alkene product would be present in the GC analysis. Explain why the alkene distribution would change, what the new product would be, and why this new product would form.

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If sodium methoxide in methanol was used , the GC analysis would look much more like the 2-butanol/sulfuric acid reaction products. In addition, a new, non-alkene product would be present in the GC analysis. When potassium t-butoxide in t-butanolis used the product is different due to the strong basicity, A new non alkene product in the GC system indicte a possible anion generation which is stabilized by the solvent leading to addition or clevage product. rhe sodium methoxide or 2-butanol in sullfuric acid behave in a similar way due to the soft nature of the reagent and th eliminationn occurs rather than a clevage.

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