Consider the cell described below at 257 K:
Sn | Sn2+ (0.811 M) || Pb2+ (0.955 M) | Pb
Given EoPb2+→Pb = -0.131 V, EoSn2+→Sn = -0.143 V. Calculate the cell potential after the reaction has operated long enough for the Sn2+ to have changed by 0.399 mol/L.
Get Answers For Free
Most questions answered within 1 hours.