Using E° = .697 V and the Nernst equation, calculate the concentration of Hg2+ in a sample of pond water if [Sn2+] = 0.500 M, [Sn4+] = 0.305 M and Ecell = 0.711 V. SHOW ALL WORK
Sn+4+2e- ---------->Sn+2, (1)
Hg+2+2e- ----------->Hg, (2)
reversing the 1st reacton, Sn+2-------->Sn+4+2e-, (1A)
Addition of 2 and 1A, Hg+2+Sn+2--------->Sn+4+Hg ,Eo=0.697V
so of electrons exchanged(n)=2, E= Eo-(0.0591/n)*logQ, Q= reaction coefficient = [Sn+4]/ [Hg+2] [Sn+2]
0.711= 0.697-(0.0591/2)*logQ
0.02955logQ= 0.697-0.711=-0.014
logQ= -0.473
Q= 0.3359
[Sn+4]/ [Hg+2] [Sn+2] = 0.3359= 0.305/(Hg+2)*0.5= 0.3359
[Hg+2]= 0.305/(0.5*0.3359)= 1.82M
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