Question

Suppose you run acid-base titration to find NaOH concentration. Based on the following information calculate Molarity of NaOH solution; Molarity of HCL = 0.1M Initial buret reading for HCL = 0.00 Final buret reading for HCLn = 10.00 Initial buret reading for NaOH = 0.00 Final buret reading for NaOH = 20.00

Answer 1

Given : molarity of HCl = 0.1 M

Initial buret reading for HCl = 0.00 mL

Final buret reading for HCl = 10.00 mL

volume of HCl used = (Final buret reading for HCl) - (Initial buret reading for HCl)

volume of HCl used = (10.00 mL) - (0.00 mL)

volume of HCl used = 10.00 mL

Similarly, volume of NaOH used = 20.00 mL

Balanced reaction : HCl (aq) + NaOH (aq) NaCl (aq) + H2O (l)

moles of HCl used = (molarity of HCl) * (volume of HCl used)

moles of HCl used = (0.1 M) * (10.00 mL)

moles of HCl used = 1.0 mmol

moles of NaOH present = moles of HCl used

moles of NaOH present = 1.0 mmol

molarity of NaOH = (moles of NaOH present) / (volume of NaOH used)

molarity of NaOH = (1.0 mmol) / (20.00 mL)

molarity of NaOH = 0.05 M