Question

how many grams of Iron (III) Sulfide form when 62.0 mL of 0.135 M iron(III) Chloride react with 45.0mL of 0.258M calcium sulfide

Answer 1

Technically speaking, Iron cannot replace Ca to form Fe3S as it is lesser reactive than calcium as proved in the reactivity series attached above.

But even then if you want to calculate the answer follow the steps -

1 Write the balanced chemical equation

2 multiply the molarity and the quantity of reactants, and their coefficients of the balanced equation

3 using mole mole analysis, subtract the things and then get the number of moles formed -> this is the answer