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A student started with 1.433 grams of copper (II) oxide and produced 3.500 g of copper...

A student started with 1.433 grams of copper (II) oxide and produced 3.500 g of copper (II) sulfate. What is the percent yield? The product is a hydrate. Use appropriate significant figures. Do not put a percent sign in the answer box. Useful information: chemical equation: CuO(s) + H2SO4 (aq) ---> CuSO4 (aq) +H2O(l) Formula weight of hydrated copper (II) sulfate = 249.6 g/mol

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Answer #1

CuO(s) + H2SO4 (aq) ---> CuSO4 (aq) +H2O(l)

1 mole of CuO react with H2SO4 to gives CuSO4

79.545g of CuO react with H2SO4 to gives 249.6g of CuSo4

1.433g of CuO react with H2So4 to gives = 249.6*1.433/79.545   = 4.496g

percent yield   =   Acual yield*100/theoritical yield

                        = 3.5*100/4.496   = 77.85%

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