Write the shorthand notation for the galvanic cells represented in:
1. Cr2O7 ^2- + Cl- --> Cr ^3+ + Cl2
2. PbO2 + Sn --> Pb ^2+ + Sn ^2+
1)
reactant side Cr has oxidation number +6 and product side it is
+3
decrase in oxidation number states that reduction of Cr take
place
Cr will act as cathode
reactant side Cl has oxidation number -1 and product side it is
0
incrase in oxidation number states that oxidation of Cl take
place
Cl will act as anode
so, reprsentation is
Cr+6/Cr+3//Cl-1/Cl
2)
reactant side Pb has oxidation number +4 and product side it is
+2
decrase in oxidation number states that reduction of Pb take
place
Pb will act as cathode
reactant side Sn has oxidation number 0 and product side it is
+2
incrase in oxidation number states that oxidation of Sn take
place
Sn will act as anode
so, reprsentation is
Pb+4/Pb+2//Sn/Sn+2
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