Question

The question asks me to balance the following redox equation using the half-reaction method: 4) MnO41-...

The question asks me to balance the following redox equation using the half-reaction method:

4) MnO41- (aq) + HS1- (aq) --> S (s) + MnO2 (s) (basic solution)

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The question asks me to balance the following redox reaction using the half-reaction method: HClO (aq)...
The question asks me to balance the following redox reaction using the half-reaction method: HClO (aq) + NO (g) --> Cl1- (aq) + HNO2 (aq) (acidic solution)
The problem asks me to balance the following redox equation using the (ion-electron) half-reaction method: 1)...
The problem asks me to balance the following redox equation using the (ion-electron) half-reaction method: 1) MnO41- (aq) + Cl1- (aq) --> Mn2+ (aq) + Cl2 (g) (acidic solution)
Balance the following redox equation in basic solution using the half-reactions method. H2O2 + Cr3+ =...
Balance the following redox equation in basic solution using the half-reactions method. H2O2 + Cr3+ = CrO42- + H2O
Balance the following redox reaction occurring in basic solution. I−(aq)+MnO−4(aq)→I2(aq)+MnO2(s) Express your answer as a chemical...
Balance the following redox reaction occurring in basic solution. I−(aq)+MnO−4(aq)→I2(aq)+MnO2(s) Express your answer as a chemical equation. Identify all of the phases in your answer.
Balance the following redox reaction in acidic solution using the half-reaction method, with smallest whole-number coefficients....
Balance the following redox reaction in acidic solution using the half-reaction method, with smallest whole-number coefficients. MnO4−(aq) + S2O32−(aq) → Mn2+(aq) + SO42−(aq) _____ MnO4−(aq) + _____ S2O32−(aq) + _____ H+(aq) → _____ Mn2+(aq) + _____ SO42−(aq) + _____ H2O(l)
Balance the Redox Equation using the 1/2 rxn method: 1.) S2O32-(aq) + I2(aq) ---> S4O62- (aq)...
Balance the Redox Equation using the 1/2 rxn method: 1.) S2O32-(aq) + I2(aq) ---> S4O62- (aq) + I-(aq) Balance the Redox Equation using the 1/2 rxn method (acidic): 1.) HSO3-(aq) + MnO4-(aq) ---> Mn2+ (aq) + SO42- (aq) 2.) H2O2(aq) ---> O2(g) Balance the Redox Equation using the 1/2 rxn method (basic): 1.) HSO3-(aq) + MnO4-(aq) ---> MnO42-(aq) + SO42-(aq) 2.) MnO42-(aq) ---> MnO2 (aq)
Balance each of the following redox reactions using the half-reaction method. a. ClO2–(aq) --> ClO2(g) +...
Balance each of the following redox reactions using the half-reaction method. a. ClO2–(aq) --> ClO2(g) + Cl–(aq) b. O2(g) + Sb(s) --> H2O2(aq) + SbO2–(aq) c. MnO4–(aq) + SO2(g) -->Mn2+(aq) + HSO4–(aq) d. CO(g) + I2O5(s) --> CO2(g) + I2(aq)
(a) Balance the following half-reactions by the ion-electron half-reaction method: (i) (acid solution) U4+ (aq) →...
(a) Balance the following half-reactions by the ion-electron half-reaction method: (i) (acid solution) U4+ (aq) → UO22+ (aq) (ii) (acid solution) Rh2+ (aq) → Rh2O3 (s) (iii) (base solution) MnO2 (s) → MnO4– (aq) (iv) (base solution) PuO3 (s) → Pu(OH)4 (s) (b) Which of the above equations are oxidation half-reactions? (c) Give the formulas of the reactants that become oxidized in the course of the reaction.
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): NO3– + I–...
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): NO3– + I– → NO + I2 (b) (acid solution): Cr2O72– + Fe2+ → Cr3+ + Fe3+ (c) (basic solution): Au(s) + CN– + O2 (g) → Au(CN)2–
Balance each redox reaction in basic solution using the half reaction method. (Please provide step by...
Balance each redox reaction in basic solution using the half reaction method. (Please provide step by step solution because I'm lost in this area) O2 + Cr3+ → H2O2 + Cr2O72- Te + NO3- → TeO32- + N2O4 IO3-+Re→ReO4- +IO- Pb2++IO3-→ PbO2 +I2 Cr2O72- + Hg → Hg2+ + Cr3+
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT