Question

Consider the balanced equation for the following reaction:

3H2O(l) + Mg3N2(aq) → 3MgO(s) + 2NH3(g)

If 57.7 grams of H2O reacts with 57.3 grams of Mg3N2, determine the limiting reagent in the reaction.

A. Mg3N2

B. H2O

C. NH3

D. MgO

Answer 1

reaction is

3H₂O_(l) + Mg₃N_2(aq) → 3MgO_(s) + 2NH_3(g)

molar mass of Mg₃N₂ = 100.9494gm/mol that mean 1 mole of Mg₃N₂ = 100.9494gm

molar mass of H₂O = 18.01528 gm/mol that mean 3 mole of H₂O = 54.04584gm

According to reaction 3 mole of water react with 1 mole of Mg₃N₂ that mean for complete reaction 54.04584 gm of water required 100.9494 gm of Mg₃N₂

then for 57.7 gm of water require = 57.7 100.9494 /54.04584 = 107.77 gm of Mg₃N₂

for 57.7 gm of water require 107.77 gm of Mg₃N₂ but Mg₃N₂ taken only 57.3 gm . thus Mg₃N₂ islimiting reagent

A. Mg₃N₂