Estimate the vapor pressure of phenol at 100 °C. for phenol, the boiling point temperature is181.8 °C, and Kf = 1.15.
At boiling point vapor pressure = 1 atm
at boiling point temperature = 181.8oC = 454.8K
Hvap = 58.8 kJ/mol = 58.8 *10^3 J/mol
ln (P2/P1) = Hvap/ R [1/ T1-1/T2]
P1 = 1atm, P2 = ?, T1 = 454.8, T2 = 373 K
ln (P2/1) = 58.8 *10^3 J/mol/ 8.314 J/K/mol [1/ 454.8-1/373]
P2 = 0.033 atm
Vapor pressure at 100oc is 0.033 atm.
Get Answers For Free
Most questions answered within 1 hours.