A gas has a volume of 3.16 L at 0 ∘C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to each of the following, if n and P do not change? Express your answer in three significant figures in degree Celsius A)1.99L B)1270mL C)11.0L D)40.2mL
A)
Given:
Ti = 0.0 oC
= (0.0+273) K
= 273 K
Vi = 3.16 L
Vf = 1.99 L
use:
Vi/Ti = Vf/Tf
3.16 L / 273.0 K = 1.99 L / Tf
Tf = 171.9209 K
Tf = -101 oC
Answer: -101 oC
B)
Given:
Ti = 0.0 oC
= (0.0+273) K
= 273 K
Vi = 3.16 L
Vf = 1270.0 mL
= (1270.0/1000) L
= 1.27 L
use:
Vi/Ti = Vf/Tf
3.16 L / 273.0 K = 1.27 L / Tf
Tf = 109.7184 K
Tf = -163 oC
Answer: -163 oC
C)
Given:
Ti = 0.0 oC
= (0.0+273) K
= 273 K
Vi = 3.16 L
Vf = 11.0 L
use:
Vi/Ti = Vf/Tf
3.16 L / 273.0 K = 11.0 L / Tf
Tf = 950.3165 K
Tf = 677 oC
Answer: 677 oC
D)
Given:
Ti = 0.0 oC
= (0.0+273) K
= 273 K
Vi = 3.16 L
Vf = 40.2 mL
= (40.2/1000) L
= 0.0402 L
use:
Vi/Ti = Vf/Tf
3.16 L / 273.0 K = 0.0402 L / Tf
Tf = 3.473 K
Tf = -270. oC
Answer: -270. oC
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