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What change in the boiling point of water is brought about by an increase of 0.01...

What change in the boiling point of water is brought about by an increase of 0.01 bar in atmospheric pressure? Answer in Kelvin.

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Answer #1

Here Atmospheric pressure P1=1 atm, T1=373K (standard boiling point of water)

P2=1+0.01/1.01325 =1.0098atm, T2=? (1atm=1.01325bar)

Using clausius claperon equation

log (P2 /P1)=(/2.303R)*(1/T1-1/T2)

Here =latent heat of vapourisation of water. =40.65kJ/mol=40650J/mol

R, universal gas constant= 8.314J/mol/K

On substituting these values, we get

log (1.0098/1)=(40650/2.303*8.314)(1/373-1/T2)

On solving we get T2=373.3K

Change in boiling point=373.3-373=0.3K

  

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