Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l) The average rate of consumption of Br− is 1.76×10−4 M/s over the first two minutes.
What is the average rate of formation of Br2 during the same time interval?
What is the average rate of consumption of H+ during the same time interval?
1)
Rate of reaction in terms of Br-:
rate of reaction = (1/5)*rate of consumption of Br-
Rate of reaction in terms of Br2:
rate of reaction = (1/3)*rate of formation of Br2
use:
(1/3)*rate of formation of Br2 = (1/5)*rate of consumption of Br-
rate of formation of Br2 = (3/5)*rate of consumption of Br-
= (3/5)*1.76*10^-4 M/s
= 1.06*10^-4 M/s
Answer: 1.06*10^-4 M/s
2)
Rate of reaction in terms of Br-:
rate of reaction = (1/5)*rate of consumption of Br-
Rate of reaction in terms of H+:
rate of reaction = (1/6)*rate of consumption of H+
use:
(1/6)*rate of consumption of H+ = (1/5)*rate of consumption of Br-
rate of consumption of H+ = (6/5)*rate of consumption of Br-
= (6/5)*1.76*10^-4 M/s
= 2.11*10^-4 M/s
Answer: 2.11*10^-4 M/s
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