Consider the following reaction: HC2H3O2(aq)+H2O(l)⇌H3O+(aq)+C2H3O−2(aq) Kc=1.8×10−5 at 25∘C If a solution initially contains 0.260 M HC2H3O2, what is the equilibrium concentration of H3O+ at 25∘C?
CH3COOH dissociates as:
CH3COOH H2O
-----> H3O+ + CH3COO-
0.26
0 0
0.26-x
x x
Kc = [H3O+][CH3COO-]/[CH3COOH]
Kc = x*x/(c-x)
Assuming x can be ignored as compared to c
So, above expression becomes
Ka = x*x/(c)
so, x = sqrt (Ka*c)
x = sqrt ((1.8*10^-5)*0.26) = 2.163*10^-3
since c is much greater than x, our assumption is correct
so, x = 2.163*10^-3 M
So, [H3O+] = x = 2.163*10^-3 M
Answer: 2.16*10^-3 M
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