Question

Calculate [H3O ] for the following solutions: 1) 3.07 × 10–3 M HBr. 2) b) 1.40...

Calculate [H3O ] for the following solutions:

1) 3.07 × 10–3 M HBr.

2) b) 1.40 × 10–2 M KOH

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Homework Answers

Answer #1

1)

HBr is a strong acid and it can dissociate completely in solution

HBr   ----> H^+   + Br^-

so the concentration of HBr is equal to the ocncentration of H+ ion in the solution

Therefore, [H3O+] = 3.07*10^-3 M

2)

KOH is a strong base and it can dissociate completely,

KOH ----> K+    +   OH^-

Therefore, [OH-] = 1.40*10^-2 M

[H+][OH-] = 1*10^-14

[H+](1.40*10^-2) = 1*10^-14

[H+] = (1*10^-14)/(1.40*10^-2) = 0.714*10^-12

Therefore, [H3O+] is 7.14*10^-13

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