Question

Part A calculate the energy of a photon of electromagnetic
radiation whose frequency is 6.78x10^12 s-1

Part B calculate the energy of a photon of radiation whose
wavelength is 325 no

Part C what wavelength of radiation has photons of energy
2.81x10^-18 J

Answer #1

h = planck constant

= (6.6*10^-34) J.s

part A

energy = h*(frequency)

= (6.6*10^-34)*6.78*10^12

= (4.5*10^-21) J

part B

energy = (h*c)/(wavelength)

wavelength = 325 nm

= (325*10^-9) m

c = speed of light

= (3*10^8) m/s

energy = (6.6*10^-34*3*10^8)/(325*10^-9)

= (6.1*10^-19) J

part C

energy = (h*c)/(wavelength)

wavelength = 325 nm

= (325*10^-9) m

c = speed of light

= (3*10^8) m/s

so,

2.81*10^-18 = (6.6*10^-34*3*10^8)/(wavelength)

wavelength = (19.8*10^-26)/(2.81*10^-18)

= (7.1*10^-8) m

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