Question

Calculate the theoretical yield for the synthesis of 2-nitrophenol and 4-nitrophenol from 190mg of phenol.

Answer 1

orto-55%(2-nitrophenol)

meta < 1% (3-nitrophenol)

para 45% (4-nitrophenol)

so...

mol of phenol = mass/MW = (190*10^-3)/94.11124 = 0.002018 mol of phenol

ratio is 1 mol of phenol --> 0.55 mol of 2-nitrophenol + 0.45 mol of 4-nitrophenol

then

0.002018 mol of phenol -->

0.55*0.002018 = 0.0011099 mol 2-nitrophenol

0.45*0.002018 = 0.0009081 mol of 4-nitrophenol

mass of 2-nitrphenol = mol*MW = 139.11 *0.0011099 = 0.1543 g = 0.1543*10^3 mg = 154.3 mg of 2-nitrophenol

then

mass of 4-nitrophenol = 0.0009081*139.11 = 0.12632 g = 126.32 mg of 4-nitrophenol