Question

The rate of formation of C in the reaction 2 A + B ---------> 3 C + 2 D is 2.2 mol/L.s. Calculate the rates of reaction of A and B, and the rate of formation of D.

Please and thank you. Please write the steps out , thank you

Answer 1

2A + B -------------- 3C + 2D

Rate of the reaction is -1/2d[A]/dt = - d[B]/dt = 1/3d[C]/dt = 1/2d[D]/dt

1/3d[C]/dt = 2.2mol/L

rate of reaction of Ais

1/2d[A]/dt = 1/3d[C]/dt

d[A]/dt= 2/3d[C]/dt

d[A]/dt = 2/3 x 2.2 = 1.47mole/L

d[A]/dt = 1.47mole/L

rate of reaction B is

d[B]/dt = 1/3d[C]/dt

d[B]/dt =1/3 x2.2= 0.733 mole/L

d[B]/dt = 0.733 mole/L

Rate of formation of D is

1/2d[D]/dt = 1/3d[C]/dt

d[D]/dt = 2/3 d[C]/dt

          = 2/3 x2.2 = 1.47 mole/L

d[D]/dt = 1.47 mole/L