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Using the following thermochemical data, calculate ΔHfˆ of Tm_2O_3(s) . 2TmCl_3(s) + 3H_2O(l) \rightarrow Tm_2O_3(s) +...

Using the following thermochemical data, calculate ΔHfˆ of Tm_2O_3(s) . 2TmCl_3(s) + 3H_2O(l) \rightarrow Tm_2O_3(s) + 6HCl(g) ΔHˆ=388.1kJ/mol 2Tm(s) + 3Cl_2(g) \rightarrow 2TmCl_3(s) ΔHˆ=−1973.2kJ/mol 4HCl(g) + O_2(g) \rightarrow 2Cl_2(g) + 2H_2O(l) ΔHˆ=−202.4kJ/mol

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Answer #1

Using the following thermochemical data,

calculate ΔHfˆ of Tm2O3(s)

The equation for formation of Tm2O3(s) will be

2Tm(s) + 3/2 O2(g) --> Tm2O3(s) ...............................................................(1)

The other equation given are

2TmCl3(s) + 3H2O(l) ---> Tm2O3(s) + 6HCl(g) ΔHˆ=388.1kJ/mol ......................(2)

2Tm(s) + 3Cl2(g) ---> 2TmCl3(s) ΔHˆ=−1973.2kJ/mol .....................................(3)

4HCl(g) + O2(g) ---> 2Cl2(g) + 2H2O(l) ΔHˆ=−202.4kJ/mol ..............................(4)

Now we will combine the equation 2,3 and 4 will be combined to form equation (1)

Equation (1) = Equation (3) + Equation (2) + 1.4 X equation (4)

ΔH (1) = ΔH (3) +ΔH (2) + 1.5 ΔH (4) = 388.1 - 1973.2 - 1.5(202.4) = -1888.7 KJ / mole

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