If 5.95 moles of an ideal gas has a pressure of 4.22 atm, and a volume of 88.83 L, what is the temperature of the sample in degrees Celsius?
Ideal gas equation
PV = nRT where, P = atm pressure= 4.22 atm
V = volume in Liter = 88.83 L
n = number of mole = 5.95 mol
R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,
T = Temperature in K = ?
We can write ideal gas equation
T = PV/nR
substitute the value in above equation
T = 4.2288.83/5.950.08205
T = 767.85 K
767.85 K = 767.85 - 273.15 = 494.70C
tempreture of sample = 494.70C
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