Question

If 5.95 moles of an ideal gas has a pressure of 4.22 atm, and a volume of 88.83 L, what is the temperature of the sample in degrees Celsius?

Answer #1

Ideal gas equation

PV = nRT where, P = atm pressure= 4.22 atm

V = volume in Liter = 88.83 L

n = number of mole = 5.95 mol

R = 0.08205L atm mol^{-1} K^{-1}
=Proportionality constant = gas constant,

T = Temperature in K = ?

We can write ideal gas equation

T = PV/nR

substitute the value in above equation

T = 4.2288.83/5.950.08205

T = 767.85 K

767.85 K = 767.85 - 273.15 = 494.7^{0}C

tempreture of sample = 494.7^{0}C

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