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If 100.0 grams of AgNO3 are combined with 25.00 grams MgCl2, what mass (in grams) of...

If 100.0 grams of AgNO3 are combined with 25.00 grams MgCl2, what mass (in grams) of AgCl(s) could form? The other product of the reaction is Mg(NO3)2(aq).

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Answer #1

   2 AgNO3 (aq)         + MgCl2 (aq)          -------->    2AgCl          + Mg(NO3)2

    2 moles                    1 mole                                    2 moles             1 mole

2x 170g                        95g                                       2x143.5g                                     mole ratio/stoichiometic ratio

     100g                         25g                                                  -                    -                        taken

25 g of magensium chloride reacts with only 89.4 g of silver nitrate, leaving some silver nitrate unreactd. Thus magnesium chloride is the LIming Reagent. Hence product is calculated from magnesium chloride onluy.

Thus the amount of silver chloride formed is = 25x2x 143.5 /95 = 75.52g

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