Consider an equilibrium mixture in a
closed vessel reacting according to the equation:
H2O(g) + CO(g) <====> H2(g) + CO2(g)
Which of the following statements will be correct if the volume of the vessel is reduced?
[H2] is INCREASE |
||
[CO] will DECREASE |
||
[CO2] will INCREASE |
||
[CO] will remain UNCHANGED |
Given,
H2O (g)+ CO (g) <====> H2 (g) + CO2 (g)
If we reduce the volume of the vessel, the pressure inside the vessel increases. Therefore, according to the Le Chatelier's principle, the equilibrium will shift in such a way so as to counteract this change i.e. the equilibrium will shift towards the side having lower number of moles of gases. Since the number of moles of gases on both sides are equal, so there won't be any effect on the equilibrium.
Hence, option D is correct. [CO] will remain unchanged.
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