Question

Consider the reaction for the Haber Process: 3H2 (g) + N2 (g) <--> 2NH3(g) A mixture...

Consider the reaction for the Haber Process: 3H2 (g) + N2 (g) <--> 2NH3(g)

A mixture of 1.0 mol each of N2, H2, and NH3 are placed into a 1.0 L flask and allowed to come to equilibrium at 500.0 C. Kp at this temperature is 1.45 x 10-5 atm-2.

A.) What is the value of Kc at this temperature? irst find the relationship between Kc and Kp in terms of RT. Then substitute T = 773K and R = 0.0821 (L x atm)/(mol x k)

(Note that PV=nRT. so P=nRT/V)

B.) Will this reaction proceed towards producte or towards reactants in order to reach equilibrium? Show how you determined your answer.

C.) Represent the equilibrium concentrations of H2, N2, and NH3 in rwema od X, where X is the moles/L of N2 produced. Substitute these equilibrium concentrations into the equilibrium constant expression.

D.) Solve this expression for X What are the largest and smallest possible values that X can have for this system?

Homework Answers

Answer #1

3H2 (g) + N2 (g) <--> 2NH3(g)

Kp = Kc(RT)n

n = 2-(3+1) = -2

R = 0.0821L-atm/mole-K

Kp = 1.45*10^-5

T   = 773K

Kp = Kc(RT)n

1.45*10^-5 = Kc(0.0821*773)-2

   Kc           = 1.45*10^-5 *4027.6

                    = 5840.02*10^-5

                   = 0.05840

Qc            = [NH3]^2/[N2][H2]^3

                    = 1^2/1*1^3   = 1

Qc>Kc The equilibrium shift to left side. The reaction proceed towards reactants

c.

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