Question

How many phosphorus atoms are contained in 158 kg of phosphorus?

Answer 1

mass of phosphorus = 158 kg

                                 = 158 x 10^3 g

moles of phosphorus = 158 x 10^3 / 30.97

                                  = 5101.7 mol

1 mol P   --------------> 6.023 x 10^23 atoms

5101.7 mol P -------------> ??

number of P atoms = 5101.7 x 6.023 x 10^23

                                = 3.07 x 10^27 atoms