Question

An investigator plots 1/v as a function of 1/(concentration of substrate) for data collected with and...

An investigator plots 1/v as a function of 1/(concentration of substrate) for data collected with and without an inhibitor. The best-fit line of the data collected in the absence of the inhibitor had a slope of 0.29 (arbitrary units of time) and a y-intercept of 0.02 (arbitrary units of time per concentration). The best-fit line of the data collected in the presence of the inhibitor had a slope that was 3.1-times as steep (arbitrary units of time) and a y-intercept of 0.02 (arbitrary units of time per concentration). If the concentration of inhibitor was 53 nM, what is the value of the inhibition constant Ki in terms of nM to the nearest tenth?

Homework Answers

Answer #1

Lineweaver-Burk equation for enzyme-substrate reaction in the absence of inhibitor:

1/V=Km/Vmax(1/[S]+1/Vmax

where V=reaction velocity

Km=michaelis-menten constant

[S]=substrate concentration

Vmax=maximum reaction velocity

So ,for plot of 1/V vs 1/[S], a straight line plot of the form y=mx+c,m=slope=Km/Vmx and c=y-intercept=1/Vmax

Given :slope=0.29=km/Vmax

y-intercept=1/Vmax=0.02

Vmax=1/0.02=50

km/50=0.29

km=50*0.29=14.5

Lineweaver-Burk equation for enzyme-substrate reaction in the presence of inhibitor:

As y-intercept=0.02, so Vmax is same in the presence and absence of indicator. So it is competitive inhibition.

Equation for competitive inhibition:

1/V=Km'(app)/Vmax(1/[S]+1/Vmax

with km(apparant)=Km(1+[I]/Ki)

Ki=inhibitor dissociation constant

slope=3.1*0.29=0.889=km(app)/Vmax

km(app)=0.889*Vmax=0.889*0.02=0.018

km(apparant)=Km(1+[I]/Ki)

0.018=14.8(1+53nM/Ki)

Ki=53.064 nM

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The following data have been collected for a simple linear regression analysis relating sales (y) to...
The following data have been collected for a simple linear regression analysis relating sales (y) to price (x): x y Price     ($) Sales (units) 4 120 7 60 5 100 8 80 In applying the least squares criterion, the slope (b) and the intercept (a) for the best-fitting line are b = -12 and a = 162. You are to conduct a hypothesis test to determine whether you can reject the null hypothesis that the population slope, β, is 0...
1. If I collected rate and concentration data for reactant Q and a plot of 1/[Q]...
1. If I collected rate and concentration data for reactant Q and a plot of 1/[Q] vs time produces a straight line plot with a slope of 0.363 M-1LaTeX: \cdot ⋅ s-1 What can you say definitively regarding the reaction order with respect to Q? Reaction IS 1st order with respect to Q Reaction IS 0th order with respect to Q Reaction IS 2nd order with respect to Q Reaction is NOT 2nd order with respect to Q 2. Which...
1. Correlations and Scatter Plots The following data set represents avg time per week spent on...
1. Correlations and Scatter Plots The following data set represents avg time per week spent on social media by age for 12 randomly chosen individuals. Age 14 18 27 21 55 46 18 26 15 17 62 41 Time (s) 240 150 135 110 45 72 150 41 200 125 31 52 a. The correlation coefficient between the two variables is found to be r = -0.84, and the standard deviation for each variable are Sage = 16.71 and Stime...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT