Question

Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species...

Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.015 M. 2 Fe2+(aq) + H2O2(aq) + 2 H+(aq) → 2 Fe3+(aq) + 2H2O(ℓ)

Please explain the steps.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). A) What is the emf of this cell...
A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). A) What is the emf of this cell when [Fe2+]= 2.0 M , [Fe3+]= 1.0×10−2 M , PO2=0.60 atm and the pH of the solution in the cathode compartment is 3.7? Express your answer using two significant figures.
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. A)   [Fe3+]= 3.05 M ; [Mg2+]= 2.5×10−3 M
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. Part A: [Fe3+]= 1.3×10−3 M ; [Mg2+]= 2.95 M Part B: [Fe3+]= 2.95 M ; [Mg2+]= 1.3×10−3 M
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. Part B: [Fe3+]= 1.6×10−3 M ; [Mg2+]= 3.30 M Part C: [Fe3+]= 3.30 M ; [Mg2+]= 1.6×10−3 M
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. 1. [Fe3+]= 2.3×10−3 M ; [Mg2+]= 2.90 M Express your answer in units of volts. 2. [Fe3+]= 2.90 M ; [Mg2+]= 2.3×10−3 M Express your answer in units of volts.
1) If I need to make voltaic cell with standard potential 1.477 V using Pt electrode...
1) If I need to make voltaic cell with standard potential 1.477 V using Pt electrode and aqueous solution (with salt bridge), which one should I choose for other electrode out of these option? Co (s), H2(g), Pb(s), Al(s), Li (s) 2) From O2 (g) + 4 H+ (aq) + 2 Fe (s) → 2 H2O (ℓ) + 2 Fe2+ (aq), E°cell = 1.670 V, how can I get ΔG° of the redox rxn, corrosion of iron in by oxygen?...
9 part 2 A voltaic cell employs the following redox reaction: Sn2+(aq)+Mn(s)→Sn(s)+Mn2+(aq) Calculate the cell potential...
9 part 2 A voltaic cell employs the following redox reaction: Sn2+(aq)+Mn(s)→Sn(s)+Mn2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions Part A standard conditions Ecell Part B [Sn2+]= 1.45×10−2 M ; [Mn2+]= 1.41 M . Express your answer using two significant figures. Ecell Part C [Sn2+]= 1.41 M ; [Mn2+]= 1.45×10−2 M . Ecell
A voltaic cell employs the reaction: 2Fe+3 (aq) + 3Mg (s) -> 2Fe (s) + 3Mg+2...
A voltaic cell employs the reaction: 2Fe+3 (aq) + 3Mg (s) -> 2Fe (s) + 3Mg+2 (aq) Calculate the Ecell at 25 degrees C under each of the following conditions. Fe+3 + 3e- -> Fe , Ered = -0.036 V 1. [Fe3+] = 1.00 M ; [Mg2+] = 1.00 M 2. [Fe3+] = 2.50 M ; [Mg2+] = 1.8x10-3 M Please show the work, thank you!
A voltaic cell utilizes the following reaction: 2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq). You may want to reference (Pages 872 -...
A voltaic cell utilizes the following reaction: 2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq). You may want to reference (Pages 872 - 877) Section 20.6 and Appendix E while completing this problem. 1.What is the emf of this cell under standard conditions? Express your answer using three significant figures. 2.What is the emf for this cell when [Fe3+]= 3.80 M, PH2= 0.95 atm, [Fe2+]= 0.0008 M, and the pH in both compartments is 3.80? Express your answer using two significant figures.
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Zn2...
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Zn2 ] = 0.837 M and [Fe2 ] = 0.0100 M. Standard reduction potentials can be found here. Zn(s)+Fe^2+(aq) <--->Zn^2+(aq)+Fe(s) E= _______ V
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT