Question

Place the following compounds in order.

CH3CH2CH2CH2CH3	CH3CH2CH2CH2OH	CH3CH2CH2CH3	KCl
A	B	C	D

(Enter the letter corresponding to each compound.)

a. lowest to highest boiling point:

lowest =

<

<

<

= highest

b. lowest to greatest vapor pressure:

lowest =

<

<

<

= greatest

Answer 1

(a).

# Ionic compounds i.e. KCl (form ionic bond) has more boiling point than organic compound which have covalent bond. Therefore, compound D i.e. KCl has highest boiling point.

# CH₃CH₂CH₂CH₂OH , form intermolecular hydrogen bonding due to the presence of O-H bond, therefore compound B i.e. CH₃CH₂CH₂CH₂OH have more boilng point than other given organic compound.

# CH₃CH₂CH₂CH₂CH₃ , form stronger van der waal's forces than CH₃CH₂CH₂CH₃ due to its more size and mass, therefore compound A i.e. CH₃CH₂CH₂CH₂OH have more boilng point than compound C i.e. CH₃CH₂CH₂CH₃ .

So,

Correct Order of lowest to highest boiling point is :

C < A < B < D

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(b). Compounds having more boiling point will form minimum vapors, therefore have lowest vapor pressure.

So,

Correct Order of lowest to greatest vapour pressure is :

D < B < A < C