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What is the total number of atoms in 0.0882 g of Co(ClO3)2? (A) 2.12*10^21 (B) 2.19*10^20...

What is the total number of atoms in 0.0882 g of Co(ClO3)2?

(A) 2.12*10^21 (B) 2.19*10^20 (C) 1.65*10^21 (D) 5.31*10^22 (E) 3.94*10^21

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Answer #1

atomicity of Co(ClO3)2   = 9

weight of substance = 0.0882g

G.M.Wt of Co(ClO3)2   = 226g/mole

no of atoms   = W*6.023*10^23*atomicity/G.M.Wt

                     = 0.0882*6.023*10^23*9/226

                    = 2.12*10^21 atoms >>>>>answer

(A) 2.12*10^21 >>>>answer

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