About how much 20gKClO3 would dissolve in 38gH2O at 70degrees Celcius?
The solubility of Potassium Chlorate in water at 70 degree centigrade is around 36-37gm/100mL water. Now at 70 degrees the density of water is around 0.98 gm/mL. Therefore 38 gm of water means 38/0.98 = 38.78 mL (approx)
Now 100 mL water can solubilize 36 gm of KClO3
therefore 38.78 mL water can solubilize 36*38.78/100 = 13.96 = 14 gm (approx).
Please note the solubility data of KClO3 is not provided so here I am using an approximate value obtained from a curve (36-37 gm/100mL). If you have an exact value, using the above procedure you can precisely calculate the amount.
Hope this will help.... Cheers!!
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