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The molar solubility of PbCl2 at 298K is 1.4422×10-2. Determine the Ksp of this salt.

The molar solubility of PbCl2 at 298K is 1.4422×10-2. Determine the Ksp of this salt.

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Answer #1

PbCl2(s) <=> Pb+2(aq) +2Cl-(aq)

Given solubility of PbCl2 = 1.4422×10-2 mol/L

Therefore [Pb+2] = 1.4422×10-2

and [Cl-] = 1.4422×10-2

Solubility product Ksp = [Pb+2] x [2 [Cl-]]2

                                   = 4 x (1.4422×10-2 )3

                                   = 11.998 x 10-6

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