104. Calculate the net constant value (Knet) for the following reactions:
2NON2+O2 Kc=2.4X1030
NO+ ½ Br2NOBr Kc=1.4
½ N2+ ½ O2 + ½ Br2 NOBR Kc net=?
we have
2NO ----------------> N2 + O2 Kc=2.4X10^30
NO + ½ Br2 -----------> NOBr Kc=1.4
therefore
½ N2 + ½ O2 + ½ Br2 ------------> NOBr
Kc net = [NOBr] / [N2]1/2 [O2]1/2 [Br2]1/2
= 1.4 / 2.4X10^30
= 9.04 X 10^-16
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