a student, not the instructor, in this class can grow their hair 36 inches in one year. Assuming that the increase in length is due only to growth of alpha-keratin, calculate the number of alpha-keratin helix turns synthesized by this student per minute. Recall that 1 inch= 2.54 cm. a) 1.34 X 10^3 turns/min b) 2.27 X 10^3 turns/min c) 3.22 X 10^3 turns/min d) 3.41 X 10^3 turns/min e) 9.42 X 10^14 turns/min
Ans. Growth rate of hair = 36 in / yr
= 36 x (2.54 cm) / yr ; [1 in = 2.54 cm]
= 91.44 cm x 108 A/ yr ; [1 cm = 108 A]
= (91.44 x 108 A) / 525600 min ; [1 yr = 525600 min]
= 17397.26 A/ min
Now,
Number of a-helix repeats formed per min =
Hair growth rate/ length of helix per turn
= (17397 A/ min) / (5.4 A/ turn)
= 3.22 x 103 trun/ min
Thus, correct option is- C
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