100.0 g of 2-BE gives 223.39 g CO2 and 106.62 g
water.
The molar masses of CO2 and water are 44 g/mol and 18
g/mol respectively.
223.39 g of CO2 corresponds to 223.39/44 = 5.08
moles
106.62 g of water corresponds to 106.62/18 = 5.93 moles of
water.
Thus, the number of moles of C present in 100 g of 2-BE is 5.08.
This corresponds to 5.08 * 12 = 60.96 g
The number of moles of H present in 100 g of 2-BE is 2 * 5.93 =
11.86. This corresponds to 11.86 * 1 = 11.86 g
Mass of oxygen present in 100 g of 2-BE = 100 - 60.96 - 11.86 =
27.18 g
1 mole of O atoms weighs 16 g.
Moles of oxygen present in 100 g of 2-BE = 27.18/16 = 1.69
The mole ratio C : H : O = 5.08 : 11.86 : 1.69 = 3 : 7 : 1.
Hence, the empirical formula of 2-BE is
C3H7O.
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