Question

The standard-state reduction potential for Cu2+ to Cu is +0.342 V versus the SHE. Given that...

The standard-state reduction potential for Cu2+ to Cu is +0.342 V versus the SHE. Given that Cu2+ forms a very stable complex with the ligand EDTA, do you expect the standard-state reduction potential for Cu(EDTA)2– to be greater than +0.342 V, less than +0.342 V, or equal to +0.342 V? Explain your reasoning.

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Answer #1

as we know that stability of complex is related with high Keq value and Keq is related with deltaG0 as given below

deltaG0 = - nRT lnKeq

means a large value of Keq leads to more negative deltaG value

and

deltaG0 is related with E0 by the relation ,

deltaG = - nFE0

therefore

more negative value of deltaG0 leads to more positive E0

therefore

we can say that formation of a very stable complex with the ligand EDTA , leads to the standard-state reduction potential for Cu(EDTA)2- to be greater than +0.342 V

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