Question

balance these half reaction with permanganate and calculate the resulting oxidation number on the manganese ions:...

balance these half reaction with permanganate and calculate the resulting oxidation number on the manganese ions:

a, MnO4^1-(aq) --->Mn2+(aq)

b,MnO4^1- (aq)--> Mn3+(aq)

c,MnO4^1-(aq)-->MnO2(S)

d,MnO4^1-(aq)-->MnO4^2-(aq)

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Homework Answers

Answer #1

a, MnO4-(aq) --->Mn2+(aq)

add H2O:

MnO4-(aq) --->Mn2+(aq) + 4H2O

add H+

8H+ + MnO4-(aq) --->Mn2+(aq) + 4H2O

balance charge

5e- + 8H+ + MnO4-(aq) --->Mn2+(aq) + 4H2O

the Mn goes from +7 to +2, gains 5 electrons

b)

MnO4- --> Mn+3

add H2O

MnO4- --> Mn+3 + 4H2O

add H+

8H + MnO4- --> Mn+3 + 4H2O

add electrons

4e- + 8H+ + MnO4- --> Mn+3 + 4H2O

Mn goes from +7 to +3, gains 4 electrons

c)

MnO4- --> MnO2

balanc eO

MnO4- --> MnO2 + 2H2O

balance H+

4H+ + MnO4- --> MnO2 + 2H2O

balance e-

3e- + 4H+ + MnO4- --> MnO2 + 2H2O

Mn goes form +5 to +4, it gains 1 electrons

d.

MnO4- --> MnO2-2

add H2O

MnO4- --> MnO2-2 + 2H2O

add H+

4H+ + MnO4- --> MnO2-2 + 2H2O

add electrons

4H+ + MnO4- --> MnO2-2 + 2H2O

5e- + 4H+ + MnO4- --> MnO2-2 + 2H2O

Mn goes from +7 to +2

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