Question

Using Appendix 2 in your textbook, what is the standard change in entropy (in J/K) at 25^oC of the reaction:

2C₆H₆(l) + 15O₂(g) --> 12CO₂(g) + 6H₂O(l)?

Answer 1

2C6H6(l) + 15O2(g) --> 12CO2(g)+6H2O(g)

?Grxn = Σ?Gproducts – Σ?Greactants

The values of ?G for the chemicals can be looked up in a thermodynamics table (should be in your book). You need to be careful to pick the values for the chemicals in the correct state.

?G (CO2, g) = -394.359 kJ/mol

?G (H2O, g) = -228.572 kJ/mol

?G (O2, g) = 0 kJ/mol <== pure element in its standard state

?G (C6H6, l) = 124.5 kJ/mol

?Grxn = [12mol(?G (CO2, g)) + 6mol(?G (H2O, g))] – [2mol(?G (C6H6, l)) + 15mol(?G (O2, g))]

?Grxn = [12mol(-394.359 kJ/mol) + 6mol(-228.572 kJ/mol)] – [2mol(124.5 kJ/mol) + 15mol(0 kJ/mo)]

PLEASE PLEASE GIVE ME THE THUMB UP

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