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Calculate the pH of 0.100 molar solution of sodium chloroacetate. Ka for chloroacetic acid = 1.4...

Calculate the pH of 0.100 molar solution of sodium chloroacetate. Ka for chloroacetic acid = 1.4 x 10^-3

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Answer #1

Calculate the pH of 0.100 molar solution of sodium chloroacetate.

Ka for chloroacetic acid = 1.4 x 10^-3

ClCH2COONa (B) + H2O ClCH2COOH (A) + OH-

Conjugate Base Week Acid

Sodium acetate is a weak base and acetic acid is a weak acid,

Therefore, we can write,

Ka(A)xKb(B) = Kw, or Kb=Kw/Ka = 10^-14/(1.4*10^-3) =7.14x10^-12 M

As the dissociation of this weak base will be very less, we can write,

cb >>> Kb, so we can use the following formula,

[OH-]^2 =Kb.cb = 7.14x10^-12x0.1

Or [OH-] = 8.45x10^-7

So, pOH = -log[OH-]= -log (8.45x10^-7) = 6.07

pH=14-pOH= 14-6.07 = 7.93

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