Hydroxylamine, NH2OH, is a weak base. A 0.010 M solution of hydroxylamine has a pH of 8.98. What is the Kb for this compound? A. 9.5 x 10-6 B. 3.1 x 10-3 C. 1.7 x 10-5 D. 9.1 x 10-11 E. 9.1 x 10-9
Hydroxylamine, NH2OH, is a weak base. A fraction of molecules in aqueous solution accepts proton from water:
NH2OH (aq) + H2O (l) ↔ NH3OH+ (aq) + OH– (aq)
0.010 M solution of hydroxylamine
PH of hydroxylamine =8.98
pH = 14 – ½ × pKb + ½ × log [B]
8.98 = 14 – ½ × pKb + ½ × log 0.010
8.98 = 14 – ½ × pKb + ½ − 2
½ × pKb = 14 – 1 – 8.98
pKb = 4.02 x2 = 8.04
−log kb = 8.04
Kb = 10−8.04 = 9.12 x 10−9
Kb = 9.12 x 10−9
Get Answers For Free
Most questions answered within 1 hours.