Consider the reaction of alcohol dehydrogenase. ethanol + NAD+ ---> acetaldehyde + NADH + H+ Which is the reducing agent for this reaction? (note the direction of the arrow)
Ethanol + NAD^+ ---> acetaldehyde + NADH + H^+
The half reactions are:
(1) Ethanol ---------à Acetaldehyde + 2H^+ + 2e (oxidation)
(2) NAD+ + 2H+ + 2e- ------->NADH + H^+ (Reduction)
Ethanol is oxidized to acetaldehyde, because it loses e-
NAD+ is reduced to NADH, because it gain of e−
NAD is the oxidizing agent. (Oxidizing agent gains e− and therefore reduced during reaction)
Ethanol is the reducing agent. (Reducing agent loses e−and therefore oxidized during reaction)
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