Question

You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...

You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.200 M sodium benzoate. How much of each solution should be mixed to prepare this buffer?

Homework Answers

Answer #1

volume of buffer solution = 100.0 mL

volume of acid + salt = 100 mL

let volume of acid = V mL

then volume of salt = (100 - V) mL

millimoles of acid = 0.1xV = 0.1V

millimles of salt = 0.2 x (100 - V) = 0.2(100 - V)

pH = pKa + log [salt /acid]

4.00 = 4.20 + log [0.2(100-V) / 0.1V]

[0.2(100-V) / 0.1V] = 0.631

20 - 0.2 V / 0.1 V = 0.631

V = 76 mL

volume of benzoic acid V = 76 mL

volume of salt (sodium benzoate )= 100 - V = 100 - 76

                        = 24 mL

volume of sodium benzoate = 24 mL

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.120 M sodium benzoate. How much of each solution should be mixed to prepare this buffer? ___ ml benzoic acid ___ ml sodium benzoate
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.180 M sodium benzoate. How much of each solutionshould be mixed to prepare this buffer? ____ mL of benzoic acid ____ mL sodium benzoate
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.180 M sodium benzoate. How much of each solution should be mixed to prepare this buffer?
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.220 M sodium benzoate. How much of each solution should be mixed to prepare tis solution?
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.240 M sodium benzoate. How much Benzoic Acid and Sodium Benzoate should be added in mL?
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.140 M sodium benzoate.
You need to prepare 100 ml of a ph=4 buffer solution using .100M benzoic acid (pka=4.20)...
You need to prepare 100 ml of a ph=4 buffer solution using .100M benzoic acid (pka=4.20) and .240M sodium benzoate. How much of each solution should be mixed to prepare this buffer? Find ml of benzoic acid and ml of sodium benzoate
1.) If a buffer solution is 0.110 M in a weak base (Kb = 5.7 ×...
1.) If a buffer solution is 0.110 M in a weak base (Kb = 5.7 × 10-5) and 0.590 M in its conjugate acid, what is the pH? 2.) You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.240 M sodium benzoate. How much of each solution should be mixed to prepare this buffer? 3.) Calculate the change in pH when 6.00 mL of 0.100 M HCl(aq) is added...
1) What is the pH of 100.0 mL of a 0.100M aqueous solution of benzoic acid...
1) What is the pH of 100.0 mL of a 0.100M aqueous solution of benzoic acid at 25C? 2) What is the pH of 100.0mL of a 0.100M aqueous solution of sodium benzoate at 25C? 3) What is the pH of a mixture of 50.0mL of 0.100M benzoic acid and 50.0mL of 0.100M sodium benzoate at 25C?
common methods to prepare a buffer. Calculate the mass of benzoic acid and sodium benzoate (in...
common methods to prepare a buffer. Calculate the mass of benzoic acid and sodium benzoate (in grams) needed to prepare 250 mL of a 0.1 M buffer at pH = 4.1. (The buffer concentration is defined as the sum of the conjugate acid concentration plus the conjugate base concentration.) The pKa of benzoic acid is 4.2
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT