Determine the pH of each of the following
solutions.
(a) 0.821 M hydrogen peroxide (weak acid with Ka
= 2.4e-12).
(b) 0.306 M boric acid (weak acid with Ka =
5.8e-10).
(c) 0.309 M pyridine (weak base with Kb =
1.7e-09).
pH calculation
(a) 0.821 M H2O2
let x amount has dissociated
Ka = [HO2-][H+]/[H2O2]
2.4 x 10^-12 = x^2/0.821
x = [H+] = 1.403 x 10^-6 M
pH = -log[H+] = 5.853
(b) 0.306 M H3BO3
let x amount has dissociated
Ka = [H2BO3-][H+]/[H3BO3]
5.8 x 10^-10 = x^2/0.306
x = [H+] = 1.332 x 10^-5 M
pH = -log[H+] = 4.875
(c) 0.309 M pyridine
let x amount has been protonated
Kb = [Hpyridine+][OH-]/[pyridine]
1.7 x 10^-9 = x^2/0.309
x = [OH-] = 2.292 x 10^-5 M
pOH = -log[OH-] = 4.64
pH = 14 - pOH = 9.36
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