Question

a solution is prepared by dissolving 56.4 grams of glucose in 0.178 kilograms of water. the final volume of the solution is 400 mililiters. calculate mole percent

Answer 1

moles of glucose = 56.4 / 180 = 0.3133

moles of water = 0.178x1000 / 18 = 9.89

mole percent of glucose = (moles of glucose / total moles ) x 100

                                      = 0.3133 / (0.3133 + 9.89) x 100

                                     = 3.07 %