Question

This is a lab question about Voltaic Cells. PLEASE ANSWER BOTH QUESTIONS.

Anode	Cathode	Voltage 1	Voltage 2	Voltage 3
Mg	Cu	1.39V	1.33V	1.35V
Cu	Ag	.42V	.42V	.42V
Mg	Ag	.98V	.98V	.98V

1. Use the standard reduction potentials from a textbook to calculate the theoretical cell potentials for the three cells you made above in the “Known Metal Cells” part. Be sure to cite your textbook.

2. Average the three cell potentials you measured for each known cell you constructed. (Three cells have been made, so there should be three averages when you’re done.)

Answer 1

The theoretical standard cell potentials of the three cells is given below

Cell 1

Anode Mg ,, Cathode Cu

E^o_cell = E_cathode - E_anode = E_{Cu2+ ---> Cu} - E_{Mg2+ ---->}E_Mg = 0.337V - (-2.356) = 2.69V

Average of the cell potentials given = 1.39 + 1.33 + 1.35 / 3 = 1.35V

Cell 2

Anode Cu ,, Cathode Ag

E^o_cell = E_cathode - E_anode = E_{Ag+ -----> Ag} - E_{Cu+ ---->}E_Cu = 0.8 - 0.337V = 0.463 V

Average of the cell potentials given = 0.42 + 0.42 + 0.42 /3 = 0.42 V

Cell 3

Anode Mg ,, Cathode Ag

E^o_cell = E_cathode - E_anode = E_{Ag+ -----> Ag} - E_{Mg2+ ---->}E_Mg = 0.8 - (-2.356V ) = 3.156V

Average of the cell potentials given = 0.98V + 0.98V + 0.98V / 3 = 0.98 V