Question

-SMΔT=SMΔT+CΔT

-S(50.97g)(70.4)=(4.18 J/ºC)(100g)(4.6)+(3.975)(4.6)

3588.288= 1922.8+18.2735

S(3588.288/3588.288)= 1941.0738/35.288= 0.5410

If (A-0)/Ax100, which is the percent of error?

Answer 1

First, what I can understand from your equation is that, all the S, M and ∆T are not same but different measurements,

therefore it will be like :

-S₁M₁∆T₁ = S₂M₂∆T₂ + C∆T₂

Now from the given values S₁ is coming out to be 1941.0738 / 3588.288

S₁ = 0.541 J / ºC

More importantly you have not provided the value of S₁ against which you want to calculate the error (or say absolute or true value of S₁ is S_true). You have got the formula just put that value in the below eqaution :

% error = ((S_true - 0.541) / S_true ) * 100