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What is the pH at the equivalence point in the titration of a 23.6 mL sample...

What is the pH at the equivalence point in the titration of a 23.6 mL sample of a 0.385 M aqueous hydrocyanic acid solution with a 0.318 M aqueous sodium hydroxide solution?

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Answer #1


HCN + NaOH ---> NaCN + H2O

at equivalence point , Formation of salt(NaCN) takes place

1 mole HCN = 1 mol NaOH

so that, pH depends on salt

No of mol of HCN reacted = 23.6*0.385 = 9.086 mmole

volume of NaOH reacted = 9.086/0.318 = 28.57 ml

concentration of salt = 9.086/(23.6+28.57) = 0.174 M

pH at equivalence point = 7+1/2(pka+logC)

pka of HCN = 9.2

               = 7+1/2(9.2+log0.174)

               = 11.22

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